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  • Gyroscope Equations

    From Corey White@21:1/5 to All on Fri Feb 7 08:24:38 2025
    Gyroscopes are well-known for their ability to maintain stability and resist
    changes in orientation. Their behavior is governed by precession, a
    principle that describes how a spinning object responds to external forces.


    If you drop a spinning gyroscope alongside a regular object, the gyroscope
    will not simply fall straight down. It will follow a slower spiraling
    path and land after the other object.

    To test this idea, imagine a heavy wheel mounted on an axle, spinning
    rapidly in a vertical plane. If you rotate the axle in a horizontal plane
    while the wheel is still spinning, the wheel will either float upward or
    sink downward, depending on the direction of rotation. This is a 90 degree
    movement up or down.

    We can describe this with math.

    d is the diameter of the wheel.
    L is the length of the axle

    We calculate the total distance traveled by a point on the wheel as it
    rotates once, while the wheel spins around the axle once.

    The axle describes a circular path of radius L, and the wheel describes a
    circular path of radius d/2.The distance traveled is the sum of these two
    circular paths.

    D1=π * d * sqrt(2)+2π * L

    This equation combines the motion of both the wheel and the axle. The 2π*L
    term represents the circumference of the circular path made by the axle

    If the wheel also moves 90 degrees vertically during the rotation, then we
    also add the vertical movement, which is simply the length of the axle, L,
    because the wheel moves up by half its diameter in the vertical direction.
    (or down)

    D2=π * d * sqrt(2)+2π*L+L

    Here, 2π*L represents the circular motion of the axle, and L represents the
    vertical distance the wheel moves during the rotation.

    You can watch the experiment here:

    https://youtu.be/GeyDf4ooPdo?si=qrxh4EmBG1IhxzkD

    The question is where the additional energy comes from to move L 90 degrees.

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  • From Bertietaylor@21:1/5 to All on Fri Feb 7 08:38:02 2025
    Thanks! A proper physics post devoid the modern physics bull*.

    Will think about it.

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  • From Bertietaylor@21:1/5 to Bertietaylor on Sun Feb 9 09:41:04 2025
    On Fri, 7 Feb 2025 8:38:02 +0000, Bertietaylor wrote:

    Thanks! A proper physics post devoid the modern physics bull*.

    Will think about it.


    The gyroscope works as no point at any edge can fall as it is always
    turning away from the line of fall, so there is all round balance. A
    still gyro will be balanced if perfectly symmetric with no extra force
    for torque. As that cannot happen it will fall. Not so for the fast
    rotating gyro. It can manage extra applied torque by precessing that is rotating around the usually vertical axis of precession.

    The gyro in the video experiment may seem to defy gravity in your
    experiment. But all that is happening is that because of vertical
    rotation movement the gravity pull on a point is pushed up or sideways
    so there is less net force acting downwards creating the anti gravity appearance.

    There will be no such effect for rotation in the horizontal plane. It
    will be equally heavy for rotation and non rotation.

    Woof-woof woof woof woof-woof woof

    Bertietaylor

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